ph為1醋酸，醋酸的離常數為Ka=1.75*10^-5，求醋酸濃度

pH=1，c(H+)=0.1mol/L，c(CH3COO-)=c(H+)=0.1mol/L

Ka=c(CH3COO-)*c(H+)/c(CH3COOH)

c(CH3COOH)=c(CH3COO-)*c(H+)/Ka=0.1*0.1/1.75*10^-5=571.43mol/L